96t^2=54

Solution for 96t^2=54 equation:

96t^2=54

We move all terms to the left:

96t^2-(54)=0

a = 96; b = 0; c = -54;
Δ = b2-4ac
Δ = 02-4·96·(-54)
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-144}{2*96}=\frac{-144}{192}
=-3/4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+144}{2*96}=\frac{144}{192}
=3/4
$